Question 481128
The one-to-one function is defined by 
f(x) = x/(8-9x) 
Find f^-1, the inverse of f . 
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1st: Interchange x and y to get:
x = y/(8-9y)
2nd: Solve for "y":
8x-9xy = y
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y+9xy = 8x
y(9x+1) = 8x
f^-1(x) = 8x/(9x+1)
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Domain: All Real Numbers except x = -1/9
Range: All Real Numbers except y = 8/9
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Cheers,
Stan H.






Then, give the domain and range of f^-1 using interval notation.