Question 481093
Person A and Person B are doing target practice. Person A hits the target with a probability of 0.8, while Person B hits the target with a probability of 0.9. 
What is the probability that Person B hit the target given that both of them fired and exactly one shot hit the target?
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The events are independent.
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P(B hit and A missed) = 0.9*0.2 = 0.18
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Cheers,
Stan H.

a. 0.18
b. 0.30
c. 0.69
d. 0.90