Question 481098
2x^3-22x^2+120x-45=0,Find value of x
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I graphed it.  There is a Real zero
around x = 0.4038..
The other zeroes are complex numbers.
{{{graph(400,400,-10,10,-800,800,2x^3-22x^2+120x-45)}}}
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Cheers,
Stan H.