Question 480982
Here's an example someone else requested.
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Regarding your "Why" question, please use Google
to find out what is said on that topic online.
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Find the normal approximation for the binomial probability that x = 6, 
where n = 15 and p = 0.3. Compare this probability to the value of P(x=6) 
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u = np = 15*0.3 = 4.5
s = sqrt(4.5*0.7) = 1.7748
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P(x = 6) = P(5.5 < x < 6.5)
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z(5.5) = (5.5-4.5)/1.7748 = 0.5634
z(6.5) = (6.5-4.5)/1.7748 = 1.1269
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P(5.5 < x < 6.5) = P(0.5634< z <1.1269) = 0.1567
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Using the binomial distribution:
P(x = 5) = binompdf(15,0.3,5) = 0.2061
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Cheers,
Stan H.