Question 481042
A doctor wants to estimate the HDL cholesterol of all 20-to 29- year-old females. How many sunjects are needed to estimate the HDL cholesterol within 3 point with 99% confidence assumming σ=15.4?
n = [zs/E]^2
n = [2.5758*15.4/3]^2
Round up to get "n".
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Suppose the doctor would be content with 95% confidence. How does the decrease in confidence affect the sample size required?
n = [1.96*15.4/3]^2
Round up to get "n"
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Cheers,
Stan H.
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A 99% confidences level level requires ___subjects.
(Round up to the nearest whole number as needed.)