Question 49623
There's no need to be shy here, "anonymous"

Factor completely:
{{{6x^2-5y-3xy+10x}}}  You can factor by "grouping".  Look for terms that have commom factors and group them with parentheses.
{{{(6x^2+10x)-(3xy+5y)}}} From the first parentheses, factor out 2x and from the second parentheses, factor out a y.
{{{(2x(3x+5))-y(3x+5)}}} Now, from this you can factor out the (3x+5)
{{{(3x+5)(2x-y)}}}...and you're done!