Question 480820
x, x+2, x+4 

(x+4)^2= x^2+(x+2)^2 +12

x^2+8x+16=x^2+x^2+4x+4+12

x^2-4x=0
x(x-4)=0
x=0 OR x=4

0,2,4
4,6,8

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