Question 480860
 <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
N=2x^2+4x+1 , where N, in thousands, have a computer x years after 1990. 
Solve in what year were there 97 thousand households with computers 
 97 = 2x^2 + 4x  1
 2x^2 + 4x - 96 = 0
 x^2 + 2x - 48 = 0
factoring
(x+8)(x-6)= 0
   x = 6 |tossing out negative solution for number of years.
 1990 + 6 = 1996, the year there were 97 thousand households with computers 

 2*6^2 + 4*6 + 1 = 72 + 24 + 1 = 97  |checking our answer