Question 480846
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Hi,
the sum of two number is 3
Let x and (3-x) represent the numbers
Question states***
 x^2 + (3-x)^2 = 12
 x^2 + 9 -6x + x^2 = 12
 2x^2 - 6x -3 = 0
 {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
 {{{x = (6 +- sqrt(60))/(4) }}} 
product of these numbers:
 {{{(6 +sqrt(60))(6- sqrt(60))/16 }}} 
  (36 -60)/16 = -24/16 = -3/2