Question 480814
Let x is the first number
then {{{(x+2)}}} is the second number, {{{(x+4)}}} is the third number
{{{x+(x+2)+(x+4)=42}}}
{{{3x+6=42}}}
{{{3x=42-6}}}
{{{3x=36}}}
{{{x=36/3}}}
{{{x=12}}}
12, 14, 16 are the numbers