Question 480753
from the first equation {{{(X+Y)/Y =4}}}
{{{X+Y=4Y}}}
{{{X=4Y-Y}}}
{{{X=3Y}}} then {{{Y=X/3}}}
from the second equation {{{(X+Z)/Z =6}}}
{{{X+Z=6Z}}}
{{{X=6Z-Z}}}
{{{X=5Z}}} then {{{Z=X/5}}}
the value of {{{Y/Z=(X/3)/(X/5)=5X/(3X)=5/3}}}
Answer E. {{{5/3}}}