Question 480756
If v,w,x,y, and z are positive consecutive integers whose sum is 0, then what is the value of z+v/y-v?
<pre>
It's impossible to have any POSITIVE numbers whose sum is 0, so 
I will assume you didn't mean "positive", otherwise there is no 
solution.  So I'll delete the word "positive" and assume you meant
this:
</pre>
If v,w,x,y, and z are consecutive <s>positive</s> integers whose sum is 0, then what is the value of z+v/y-v?
<pre>
You didn't put any parentheses in to show where numerators and 
denominators begin and end, so I can't tell whether you mean

this:

{{{z+v/y-v}}}, 

or this,

{{{z + v/(y-v)}}}, 

or this:

{{{(z+v)/(y-v)}}}


The only 5 consecutive integers that have sum 0 are -2,-1,0,1,2, so

v=-2, w=-1, x=0, y=1, z = 2

If you meant this:

{{{z+v/y-v}}}, then it's {{{2+(-2)/1-(-2) = 2-2+2=2}}}  

If you meant this:

{{{z + v/(y-v)}}}, then it's {{{2 + (-2)/(1-(-2))= 2+ (-2)/(1+2)= 2-2/3=6/3-2/3=4/3)}}}  

If you meant this:

{{{(z+v)/(y-v)}}}, then it's {{{(2+(-2))/(1-(-2))= (2-2)/(1+2)=0/3=0}}}.

You have to let us know using parentheses where numerators and
denominators start and end. 

Edwin</pre>