Question 480704
Perimeter of a triangle={{{a+b+c}}}

Let Largest side be=a
Let smallest side=b
3rd side=c


The largest is 4 inches less than twice the smallest
So, {{{a=2(b)-4}}}
The third is 10 inches longer than smallest
So, {{{c=10+b}}}


P=a+b+c
substitute a and c in the above equation.
{{{86=(2(b)-4)+b+(10+b)}}}
{{{86=2b-4+b+10+b}}}
{{{86=4b+6}}}
{{{80=4b}}}
{{{4b=80}}}
{{{b=20}}}

So smallest=20 inches.
The largest{{{a=2(b)-4}}} {{{a=2*20-4}}} So{{{a=36}}}inches.
The 3rd side{{{c=10+b}}} {{{c=10+20}}} So {{{c=30}}}inches.