Question 480720


{{{a^3 - 2a^2 -35a}}}


={{{a(a^2 -2a -35)}}}

={{{a(a^2 - 2a -35)}}}........the two numbers that multiply to {{{-35}}} and add to {{{-2}}} are: {{{5}}} and {{{-7}}}.......so, replace {{{-2a}}} with {{{5a-7a}}}

={{{a(a^2 +5a-7a -35)}}}...group

={{{a((a^2 +5a)-(7a+35))}}}

={{{a(a(a +5)-7(a+5))}}}

={{{a(a-7)(a+5)}}}