Question 49576
Multiply:
{{{((-3)a^2b/35a^5)(14a^3b^2/-9b^4)}}} You can start with the numbers by canceling common factors where possible. For the 14 and 35, 7 is a common factor, and for the -3 and -9, -3 is a common factor.

{{{(a^2b/5a^5)(2a^3b^2/3b^4)}}} Now the variables, a and b. If you have trouble seeing exactly what can be canceled, you can rewrite the expression as follows:

{{{((a*a*b)/(5*a*a*a*a*a))((2*a*a*a*b*b)/(3*b*b*b*b))}}}
Now, for every a in the top, cancel an a in the bottom...one-for-one. Do the same with the b's until you get:
{{{(b/(5*a*a*a))((2*a*a*a)/(3*b*b))}}} Continue the canceling.
{{{(1/5)(2/(3*b))}}} Finally, multiply the numerators and the denominators.
{{{2/15b}}}