Question 480567
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There are 5 boys out of 9 people, so the probability of selecting a boy as President is *[tex \Large \frac{5}{9}].  Given that a boy is selected as President and we presume that the club would not select the same person to serve as President and Vice-President simultaneously, the probability that a girl is selected as Vice-President is 4 girls out of the 8 people who remain once the one boy selected as President has been subtracted.  The probability of both occurences is the product:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{5}{9}\ \times\ \frac{1}{2}\ =\ \frac{5}{18}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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