Question 480275
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You have both equations set up correctly, now just substitute:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ +\ B\ =\ 41]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ 2B\ +\ 2]


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (2B\ +\ 2)]


goes in place of *[tex \Large A] in the first equation resulting in:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2B\ +\ 2\ +\ B\ =\ 41]


Solve for *[tex \Large B].  Then calculate *[tex \Large 41\ -\ B].  Check your work by calculating *[tex \Large 2B\ +\ 2] which, given proper work, should equal *[tex \Large 41\ -\ B]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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