Question 480275
A and B have a combined age of 41 but A is two more than twice B's age...what are their ages? the formula is A+B=41,A is two more than twice B's age..
A = 2b + 2
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A + B = 41
A -2B =  2
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Subtract and solve for B:
3b = 39
B = 13
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Solve for A:
A + B = 41
A + 13 = 41
A = 28
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Cheers,
stan H.
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