Question 49533
you don't have brackets around 10 + sqrt(16 - 9) so i do not know if the denominator of 8 is under everything, as you wrote or just the radical part... that is for you to clarify to yourself.


If it is everything, then {{{ (10+sqrt(7))/8 }}} is correct. Do not evaluate it...the question asks you to simplify NOT evaluate. Your answer is incorrect in that it is a rounded up version of a never ending decimal. That is why we write radicals... they are the EXACT number.


What we could do is:
{{{ (10+sqrt(7))/8 }}}
{{{ (10/8)+(sqrt(7))/8 }}}
{{{ (5/4)+(sqrt(7))/8 }}}


but this is questionably NOT simpler than {{{ (10+sqrt(7))/8 }}}... so leave it alone as {{{ (10+sqrt(7))/8 }}} as your answer.


jon.