Question 479938
x^2+6x+3=0

Find the roots of the equation by quadratic formula					
					
a=	1	,b=	6	,c=	3
					
b^2-4ac=	36	+	-12		
b^2-4ac=	24				
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}					
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}					
{{{x1=(-12+21)/(2)}}}					
x1=(	-6	+	4.9	)/	2
x1=	-0.55				
x2=(	-6	-4.9	) /	2	
x2= 	-5.45				
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