Question 6175
(((n^3=9n}}}
You divide both sides by n
{{{n^3/n=9n/n}}} The property for diving exponents is {{{b^n/b^m=b^(n-m)}}}
{{{n}}} has an exponent of 1 = ({{{n^1}}})
Thus you get {{{n^2=9}}}
Hope this helps