Question 478098
Solve for x
{{{ log(x,8x-3) - log(x,4) = 2 }}}
log_x ((8x-3)/4)) = 2
(8x-3)/4=x^2
8x-3=4x^2
4x^2-8x+3=0
Solving x=3/2 or x= 1/2