Question 479562
{{{n=1}}}....{{{a[1]=0=(-1)^(1-1)*(1-1)^2}}}
{{{n=2}}}....{{{a[2]=-1=(-1)^(2-1)*(2-1)^2}}}
{{{n=3}}}....{{{a[3]=4=(-1)^(3-1)*(3-1)^2}}}
{{{a[n]=(-1)^(n-1)*(n-1)^2}}} if n=1,2,3,.....