Question 479101
The unit's digit of a two-digit number is one-third the tens digit.
When the digits are reversed, the new number is two more than four times the tens digit.
 Find the original number?
:
Let x = the tens digit
Let y = the units
:
10x + y = "the number"
:
Write an equation for each statement:
"
"The unit's digit of a two-digit number is one-third the tens digit."
y = {{{1/3}}}x
or
3y = x
:
"When the digits are reversed, the new number is two more than four times the tens digit."
10y + x = 4x + 2
10y = 4x - x + 2
10y = 3x + 2
Replace x with 3y
10y = 3(3y) + 2
10y = 9y + 2
10y - 9y = 2
y = 2 is the units
then
3(2) = 6 is the 10's digit
:
62 is the number
:
:
You can confirm this in the statement
"When the digits are reversed, the new number is two more than four times the tens digit. "