<PRE><B>Question 479285</B>
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You cannot prove such a premise in general.


Construct a circle.


Construct a diameter of the circle.


Construct any chord parallel to that diameter.


The diameter is a chord by definition, but has an included arc greater in measure than any lesser chord.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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