Question 479216

the diagonals of a rhombus are {{{36cm}}} and {{{24cm}}}

the diagonals are all crossed at one point...at this point the lengths are perfectly split in half resulting in the short diagonal {{{24cm}}} becoming only 12cm and the {{{36cm}}} to become {{{18cm}}}

the diagonal lines of the perimeter by using the Pythagoras' theorem:

{{{c^2=a^2+b^2}}}...-> {{{c}}} being the unknown (one of the sides or the hypotenuse that is diagonal)

{{{c^2=(12cm)^2+(18cm)^2}}}

{{{c^2=144cm^2+324cm^2}}}

{{{c^2=468cm^2}}}

{{{c=sqrt(468cm^2)}}}

{{{c=21.63cm}}}

Now you've got one of the sides solved, multiply it by {{{4}}} since {{{rhombus}}} has {{{4}}}{{{ equal}}} sides.

{{{P=4*21.63cm}}}

{{{P=86.52cm}}}