Question 479159
Probably the best way to approach this problem would be with a chart.

Value || 2/x ...||   2/x^2
----------------------------
-2..... || -1........|| 1/2
-1......|| -2........|| 2
0.......|| undefined.||undefined
1.......|| 2.........|| 2
2.......|| 1.........|| 1/2
3.......|| 2/3.......|| 1/8

plug in the values of x into your equation, you can see when x is > 1 the equation result is true. 
Cleomenius.