Question 479142
the Pythagorean theorem {{{a^2+b^2=c^2}}}
{{{c=10sqrt(2)}}}
The triangle is right and isosceles, so {{{a=b}}}
{{{a^2+a^2=(10sqrt(2))^2}}}
{{{2a^2=100*2}}}
{{{a^2=100}}}
{{{a=10}}}
Answer 10 and 10