Question 478865
the problem states determine the nature of solutions of the equation y^2=2/7y+1/7.
Assume the problem is:
{{{y^2 = (2/7)y + 1/7}}}
:
{{{y^2 - (2/7)y - 1/7}}} = 0
from the sign of the 3rd term (-1/7) we know one solution will be negative and one solution will be positive
:
You can solve it using the quadratic formula, make the coefficients integers;
multiply by 7. Then a=7, b=-2, c=-1