Question 478912
{{{4x^2-16}}} is the difference of two squares.
In general, these will factor as follows:
{{{a^2-b^2 = (a+b)(a-b)}}} so, in this problem we get:
{{{4x^2-16 = (2x)^2-(4)^2}}} = {{{(2x+4)(2x-4)}}}