Question 49410
Solve {{{5x^2+3x = 7}}} by using the quadratic formula: {{{x=(-b+-sqrt(b^2-4ac))/2a}}}

Start by putting your equation in "standard form": {{{ax^2+bx+c = 0}}}

{{{5x^2+3x-7 = 0}}} Compare with the standard form: a = 5, b = 3, and c = -7 Substitute these into the quadratic formula and solve for x.

{{{x = (-3+-sqrt(3^2-4(5)(-7)))/2(5)}}} Simplify.
{{{x = (-3+-sqrt(9+140))/10}}}
{{{x = (-3+-sqrt(149))/10}}}

Roots are:
{{{x = -3/10+(sqrt(149))/10}}}
{{{x = -3/10-(sqrt(149))/10}}}