Question 478713
5x+3y<15
5x-4y<20

First we find the boundary of each line
5x+3y=15............1
5x-4y=20............2

equation1			
when x=	0	y=	5	(	0	,	5	)
when y =	0	x=	3	(	3	,	0	)
Equation 2								
when x=	0	y=	-5	(	0	,	-5	)
when y =	0	x=	4	(	4	,	0	)
The Boundary
{{{drawing(300,300,-10,10,-10,10,circle(0,5,0.3),circle(3,0,0.3),circle(0,-5,0.3),circle(4,0,0.3),graph(300,300,-10,10,-10,10,y=(-5/3)x+5,y=(5/4)x-5))}}}

The Inequality

{{{drawing(300,300,-10,10,-10,10,circle(0,5,0.3),circle(3,0,0.3),circle(0,-5,0.3),circle(4,0,0.3),graph(300,300,-10,10,-10,10,y<(-5/3)x+5,y<(5/4)x-5))}}}


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