Question 478606
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Hi,
<img src=" http://upload.wikimedia.org/wikipedia/commons/thumb/9/96/Triangle.Equilateral.svg/200px-Triangle.Equilateral.svg.png " />
equilateral triangle with side of 12. | Note: Altitude bisects the base 
h = sqrt(12^2 - 6^2) = sqrt(108) = 6sqrt(3)
A = (1/2)b*h = (1/2)12*6sqrt(3) = 36sqrt(3)