Question 478580
Solve for x:
{{{6x^2 = 31x-5}}} Subtract 31x from both sides.
{{{6x^2-31x = -5}}} Now add 5 to both sides.
{{{6x^2-31x+5 = 0}}} Factor this quadratic equation.
{{{(6x-1)(x-5) = 0}}} Apply the "zero product" rule.
{{{6x-1 = 0}}} or {{{x-5 = 0}}} therefore:
{{{6x = 1}}} and {{{highlight(x = 1/6)}}} or...
{{{highlight(x = 5)}}}