Question 478578
V = 2*(ab + bc + ac)
reorder the terms to get:
V = 2*(ab + ac + bc)
factor out the a to get:
V = 2*(a(b+c) + bc)
expand the equation to get:
V = 2a(b+c)+2bc
subtract 2bc from both sides of the equation to get:
V-2bc = 2a(b+c)
divide both sides by (b+c) to get:
(V-2bc)/(b+x) = 2a
divide both sides by 2 to get:
(V-2bc)/(2(b+c)) = a
commute to get:
a = (V-2bc)/(2(b+c))
assuming a = 1, b = 2, c = 3, your original equation gets:
V = 2*(2+6+3) = 2*11 = 22
plug the values for V and b and c into the final equation to get:
(22-12)/(2(5)) = a which becomes:
10/10 = 1 which is the value of a we started out with, so the conversion formula looks good.
i think that's your answer.
check it out for yourself to see if it works for you.