Question 478501
First put in order. 
3x^2  -26x + 35 = 0.

Next, assign a, b, and c.

a = 3
c = -26
c = 35

The formula is (-b +,-   (sqrt( b^2  - 4ac))/ 2a  

(26  +,-       sqrt( (-26)^2   - 4(3)(35)  )  / 2(3)


(26   +,-       sqrt(676  -   420)  ) /6

(26   +,-  sqrt ( 256)) / 6.
(26  + 16) /6   =  7
(26  - 16) /6   = 1.667

If you plug these into your original formulas, they will both check out.

Cleomenius.