Question 478501
{{{3x^2+35=26x}}}...first move {{{26x}}} to the left

{{{3x^2-26x+35=0}}}..now use quadratic formula

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}...note: {{{a=3}}}, {{{b=-26}}} and {{{c=35}}}


{{{x = (-(-26) +- sqrt( (-26)^2-4*3*35 ))/(2*3) }}}


{{{x = (26 +- sqrt(676-420 ))/6 }}}


{{{x = (26 +- sqrt(256))/6 }}}


{{{x = (26 +-16)/6 }}}


solutions:

{{{x = (26 +16)/6 }}}


{{{x = 42/6 }}}


{{{x = 7}}}

or

{{{x = (26 -16)/6 }}}


{{{x = 10/6 }}}


{{{x = 5/3}}}




{{{ graph( 500, 500, -10, 10, -50, 50, 3x^2-26x+35) }}}