Question 478470
2^x = 30 
Take the log of both sides to get:
x(log(2)) = log(30)
x = [log(30)]/[log(2)]
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5^(x - 1) = 3x
Graph and left side.
Graph the right side.
Find any points of intersection.
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3.53^(x + 1) = 65.4
(x+1)log(3.53) = log 65.4
x+1 = [log(65.4)]/[log(3.53)]
etc.
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16^(x - 4) = 3^(3 - x)
(x-4)log(16) = (3-x)log(3)
[log(16)+log(3)]x = 4log(16)+3log(3)
Solve for "x"
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7^(x - 2) = 5^x
Same process as above.
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Cheers,
Stan H.