Question 49088
{{{z=1/(2^0.5)(i-(3^0.5))}}}={{{1/(sqrt(2)i-sqrt(6))}}}={{{1/(sqrt(2)i-6)*(sqrt(2)i+sqrt(6))/(sqrt(2)i+sqrt(6))}}}={{{(sqrt(2)i+sqrt(6))/(2i^2-6)}}}
since {{{i^2=-1}}}, that equals {{{(sqrt(2)i+sqrt(6))/(-6-2)}}}={{{-(sqrt(2)i+sqrt(6))/8}}}