Question 478435
{{{system(3x-y=12, 2x-2y=20)}}}
From the first equation {{{-y=12-3x}}}, or {{{y=-12+3x}}} substitute into the second equation
{{{2x-2(-12+3x)=20}}}
{{{2x+24-6x=20}}}
{{{-4x=20-24}}}
{{{-4x=-4}}}
{{{x=1}}}
substitute {{{x=1}}} into the first equation {{{y=-12+3*1}}}
{{{y=-9}}}
Answer (1,-9)