Question 478401
y=6x^2+13x+6

when x=0 y =6  (0,6)

When y=0 , 6x^2+13x+6=0
6x^2+9x+4x+6=0
3x(2x+3)+2(2x+3)=0
(2x+3)(3x+2)=0
x=-3/2OR x=-2/3 

(-3/2,0) and (-2/3,0)

When x= 0.5 , y = 12.5 ( 0.5,14)
when x=-0.5, y= 1)

Calculate y for a few values of +/-x plot the points and you will get a graph as shown below
{{{drawing(300,300,-10,10,-10,10,circle(0,6,0.3),circle(-3/2,0,0.3),circle(-2/3,0,0.3),circle(0.5,12,0.3),circle(-0.5,1,0.3),graph(300,300,-10,10,-10,10,y=6x^2+13x+6))}}}
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