Question 478397
3x^2-26x+35=0
Find the roots of the equation by quadratic formula							
							
a=	1	b=	-26	c=	35		
							
b^2-4ac=	676	-	-140				
b^2-4ac=	536			
{{{sqrt(	536	)}}}=	23.15
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(	26	+	23.15	)/	2		
x1=	24.58	===>172/7				
x2=(	26	-23.15	) /	2			
x2= 	1.42	===>	10/7