Question 478238
If {{{x[1]}}}, {{{x[2]}}} are solutions of the quadratic equation, then 
{{{(x-x[1])(x-x[2])=0}}}
{{{x[1]=-sqrt(10)}}}, {{{x[2]=6sqrt(10)}}}
The equation {{{(x-(-sqrt(10)))(x-6sqrt(10))=0}}}
{{{(x+sqrt(10))(x-6sqrt(10))=0}}}
{{{x^2-6x*sqrt(10)+x*sqrt(10)-6(sqrt(10))^2=0}}}
{{{x^2-5x*sqrt(10)-60=0}}}