Question 478231
Since this is a right triangle, we can use a^2 + b^2 = c^2

Let one leg be x.
Let the other leg be x + 7.

x^2  + (x + 7)^2  =  289
x^2  + x^2  + 14x  + 49 = 289
2x^2  + 14x  -  240  = 0
2 ( x^2  + 7x - 120) = 0
2 (x - 8) ( x + 15) = 0

x will = 8, one leg of the triangle.
8 + 7 = 15, the other leg of the triangle.
8^2   +    15^2   =   17^2
64   +     225     =   289, The results do check.

Cleomenius.