Question 46732
Hopefully someone that knows better can confirm or correct, but I think the answer is 120. Here is how I got there: 
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Center: <b>2</b> ways to select one center
Forward: 5C2 or <b>10</b> ways to select two forwards
Guard: 4C2 or <b>6</b> ways to select two guards
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For the forwards and guards, I used what is called a Combinations Formula. One can look up how to use it on Wikipedia or use the =COMBIN(x,y) function in Excel. The long hand version that one would have to use to solve by hand is 5!/2!*(5-2)! As you can see, for forwards I had '5' for the number of available forwards I had to choose from and '2' for the amount that I would select from the available group. Now onto the rest of the solution...
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I multiply the possibilities that I have for each position: 2*10*6 which equals 120.