<PRE><B>Question 478052</B>
An agency monitors the speed with which it repairs badly damaged communities. Suppose past data indicates the likelihood is 0.75 that repairs in a similar community can be resolved in the same day . For the first five reports given on a day , what is the probability that 
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Binomial Problem with n = 5 and p = 0.75
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(1)Exactly three report will be resolved on the same day. 
Ans: 5C3*0.75^3*0.25^2 = 0.2637
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(2)No report will be resolved on the same day
Ans: 0.25^5
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(3)all reports will be resolved on the same day
Ans: 0.75 ^5 = 0.2373
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(4)what is the expected amount of repairs to be resolved.
E(x) = np = 5*0.75 = 15/4 = 3.75
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cheers,
Stan H.
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