Question 478045

let's the number be {{{x}}}

If 5 times the square of an integer {{{5x^2}}} 

is decreased by {{{32}}} times the number {{{5x^2-32x}}}

the result is {{{21}}}...->{{{5x^2-32x=21}}}....solve quadratic

{{{5x^2-32x-21=0}}}...use quadratic formula


*[invoke quadratic_formula 5, -32, -21, "x"]


check our solutions:

{{{x=7}}} 

{{{5*7^2-32*7=21}}}

{{{5*49-224=21}}}

{{{245-224=21}}}

{{{21=21}}}

or {{{x=-3/5}}}

{{{5*(-3/5)^2-32*(-3/5)=21}}}

{{{5*(9/25)+32*(3/5)=21}}}

{{{45/25+96/5=21}}}

{{{1.8+19.2=21}}}

{{{21=21}}}