Question 478045
let the integer be x

5x^2-32x=21

5x^2-32x-21=0
Find the roots of the equation by quadratic formula							
							
a=	5	b=	-32	c=	-21		
							
b^2-4ac=	1024	-	420				
b^2-4ac=	1444		
{{{sqrt(	1444	)}}}=	38
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}
							
x1=(	32	+	38	)/	10		
x1=	7		    				
x2=(	32	-38	) /	10			
x2= 	-0.6				
Ignore 	-0.6


7 is the number