Question 477997
Let the numbers be
x,x+2,x+4,x+6

x+x+2= (x+4)(x+6)-70

2x+2=x^2+10x+24-70

x^2+10x-2x+24-70-2=0
x^2+8x-48=0
x^2+12x-4x-48=0
x(x+12)-4(x+12)=0
(x+12)(x-4)=0

x=-12 OR x=4

-12,-10,-8,-6

OR
4,6,8,10