Question 478031
Part a: Solve for x: 
a=bx^(-2)
Multiply thru by x^2 to get:
ax^2 = b
x^2 = b/a
x = +/-sqrt[b/a]
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Part B: 
Given the following information, solve for b: a = 1000, x = 2325
b = ax^2
b = 1000*2325^2
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Also: a = 1000, x = 245
b = 1000*245^2
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2. 
The Pythagorean Theorem is a^2+b^2=c^2. 
Solve the equation for b.
b^2 = (c^2-a^2)
b = +/-sqrt(c^2-a^2)
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Part 2: If c = 225, and a = 121, solve for b.
Solutions:
b = +/-sqrt(225^2-121^2)
b = +/-189.6945
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Cheers,
Stan H. 
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